4n^2-10=3n

Solution for 4n^2-10=3n equation:

4n^2-10=3n

We move all terms to the left:

4n^2-10-(3n)=0

a = 4; b = -3; c = -10;
Δ = b2-4ac
Δ = -32-4·4·(-10)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-13}{2*4}=\frac{-10}{8}
=-1+1/4
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+13}{2*4}=\frac{16}{8}
=2
$